C3H8 + 502 —-> 3CO2 + 4H20 (a) if I start with 5 g of C3H8, what is my theoretical yield of water?

C3H8 + 502 —-> 3CO2 + 4H20 (a) if I start with 5 g of C3H8, what is my theoretical yield of water?

(you have to solve this by mass to mass stoichiometry)*

A. 8.2 g of H20
B. 9.1 g of H20
C 8.7g of H20
D. 6.15 g of H20

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